If the pice of sugar rises from Rs. 6 per kg to Rs. 7.50 per kg, a person, to have no increase in his expenditure on sugar, will have to reduce his consumpion of sugar by
A) 15
B) 20
C) 25
D) 30
Answer: B) 20
Explanation:
Let original consumption = 100 kg and new consumption = x kg,
So, 
Reduction in consumption = 20%.
A district has 64000 inhabitants. If the population increases at the rate of 2 * 1/2 % per annum, then the number of inhabitants at the end of 3 years will be :
A) 65380
B) 68921
C) 70987
D) 72345
Answer: B) 68921
Explanation:
Population afer 3 years = 64000 * (1 + 5/(2 *100) )^3 = (64000 * 41/40 * 41/40 * 41/40 ) = 68921..
A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :
A) 21.6 %
B) 15.3 %
C) 14.6 %
D) 12.5 %
Answer: A) 21.6 %
Explanation:
Total money = 
25 paise coins removed =
50 paise coins removed = 
Money removed =
Required percentage = 
In a City, 35% of the population is composed of migrants, 20% of whom are from rural areas. Of the local population, 48% is emale while this figure for rural and urban migrants is 30% and 40% respectively. If the total population of the city is 728400, what is its female population ?
A) 856678
B) 860990
C) 896660
D) 908790
Answer: C) 896660
Explanation:
Migrants = 35 % of 728400 = (35x/100 * 728400) = 254940.
local population = (728400 - 254940) = 473460.
Rural population = 20% of 473460 = 94692.
Urban population = (254940 - 94692) = 160248.
Female population = 48% of 473460 + 30% of 94692 + 40% of 160248
= (48/100 * 473460 + 30/100 * 94692 + 40/100 * 160248)
= 227260.8 + 28407.6 + 64099.2 = 896660
The sum of the number of boys and girls in a school is 150. if the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is :
A) 60
B) 70
C) 80
D) 90
Answer: A) 60
Explanation:
We have : x + x% of 150 = 150
=>
=>
=>
A candidate scoring 25% in an examination fails by 30 marks , while another candidate scores 50 % mark, gets 20 marks more than the minimum pass marks . Find the minimum pass marks. Find the minimum pass percentage.
Answer
Let x be the maximum marks,
Then (25% of x)+30 = (50% of x)-20
Hence maximum marks = 200
Minimum pass marks =
Hence, minimum pass marks = 
In some quantity of ghee, 60% is pure ghee and 40% is vanaspati. If 10 kg of pure ghee is added, then the strength of vanaspati ghee becomes 20%. The original quantity was :
A) 10 kg
B) 15 kg
C) 20 kg
D) 25 kg
Answer: A) 10 kg
Explanation:
Let the original quantity be x kg. Vanaspati ghee in x kg = (40x / 100 )kg = (2x / 5) kg.
Now, (2x/5)/(x + 10) = 20/100 <=> 2x / (5x + 50) = 1/5 <=> 5x = 50 <=> x = 10.
Entry fee in an exhibition was Rs. 1. Later, this was reduced by 25% which increased the sale by 20%. The percentage increase in the number of visitors is :
A) 20 %
B) 40 %
C) 60 %
D) 80 %
Answer: C) 60 %
Explanation:
Let the total original sale be Rs. 100. Then, original number of visitors = 100.
New number of visitors = 120/0.75 = 160.
Increase % = 60 %.
In an election only two candidates contested 20% of the voters did not vote and 120 votes were declared as invalid. The winner got 200 votes more than his opponent thus he secured 41% votes of the total voters on the voter list. Percentage votes of the defeated candidate out of the total votes casted is:
A) 47.5%
B) 41%
C) 38%
D) 45%
Answer: D) 45%
Explanation:
Let there be x voters and k votes goes to loser then
0.8x - 120 = k + (k + 200)
k+200 = 0.41x
and (k + 200) =1640
Therefore 
If x is 80% of y, then what percent of 2x is y?
A) 65.5 %
B) 64.5 %
C) 63.5 %
D) 62.5 %
Answer: D) 62.5 %
Explanation:
x = 80 % of y 
Required percentage = 
1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is :
A) 58
B) 62 *2/3
C) 64
D) 67
Answer: B) 62 *2/3
Explanation:
Total number of students = 1100 + 700 = 1800.
Number of students passed = (42% of 1100 + 30% of 700) - (462 + 210) = 672.
Number of failues = 1800-672 = 1128.
Percentage failure = (1128/1800 * 100 )% = 62 * 2/3 %.
Of the 1000 inhabitants of a town, 60 % are males of whom 120 % are literate. If, of all the inhabitants, 25% are literate, then what percent of the females of the town are literate ?
A) 32.5 %
B) 43 %
C) 46.6 %
D) 53.2 %
Answer: A) 32.5 %
Explanation:
Number of males = 60% of 1000 = 600. Number of females = (1000 - 600) = 400.
Number of literates = 25% of 1000 = 250.
Number of literate males = 20% of 600 = 120.
Number of literate females = (250 - 120) = 130.
What percent of 7.2 kg is 18 gms ?
A) .25%
B) .5%
C) .75%
D) 1%
Answer: A) .25%
Explanation:
Required percentage = (18/7200 * 100)% = 1/4% = 0.25%
In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State ?
A) 4000B) 8000C) 12000D) 16000
Answer: B) 8000
Explanation:
Let the number of candidates appeared from each state be x.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000
The population of a town was 1,60,000 three years ago, If it increased by 3%, 2.5% and 5% respectively in the last three years, then the present population in
A) 155679
B) 167890
C) 179890
D) 177366
Answer: D) 177366
Explanation:
Present population = 160000 * (1 + 3/100)(1 + 5/200)(1 + 5/100)
= 177366.
if the price of a book is first decreased by 25% and then increased by 20%, then the net change in the price will be :
A) 10
B) 20
C) 30
D) 40
Answer & ExplanationAnswer: A) 10
Explanation:
Let the original price be Rs. 100.
New final price = 120 % of (75 % of Rs. 100) = Rs. (120/100 * 75/100 * 100) = Rs. 90.
Decrease = 10%
Sujit runs at 6 km/hour and Rana at 8 km/hour .Rana catches Sujit in 9 minutes.What was the distance between sujit and Rana, when Rana started?
(a) 223 metres
(b) 153 metres
(c) 300 metres
(d) 350 metres.
Ans 9. 300 metres
Note : Try it. Practice question
Walking at 5/4th of his usual speed, Mr Subramaniam his office 10 minute early .Find hid usual reaching time.
(a) 20 min.
(b) 12 1/2 min.
(c) 40 min.
(d) 50 min.
Ans 8. 50 min.
Note : Try it. Practice question
Note : Try it. Practice question
Ashok left mathura at 5 a.m. An hour and a half later Brijesh left Mathura, his speed bring 5 kmph higher than that of Ashok. At 9:30 p.m. on the same day the distance between Ashok and Brijesh was 21 km.What is the speed of Ashok in kmph?
(a) 80 or 20
(b) 75 or 25
(c) 70 or 30
(d) 64 or 36
Ans 7. 64 or 36
Hint: Ashok travles for ( 12-5) + 9:30 hours till 9:30 p.m. Brijesh travels for (12-6:30) + 9:30 p.m.
There are two possibilities:
Ashok could be leading Brijesh or Brijesh could be leading Ashok.
A person covers a certain distance on a train. If the train moved 6 km/hour faster, it would take 40 minutes less. If it moved 3 km/hour slower , it would take 30 minutes more .Find the distance.
Ans 6.
Without stoppages, a train travels a certain distance with an average speed of 90 km/hour, and with stoppages it cover the same distance with an average speed of 60 km/hour. Find the stoppage time per hour of the train.
Ans 5.
Two trains are running at 40 km/hour and 20 km/hour respectively in the same direction . The faster train completely passes a man siting in slower train in 5 seconds. Find the length of faster train.
Ans 4.
Two trains 121 metres long and 99 metres long are running in opposite direction with speeds of 40km/hour and 32 km/hour respectively . In what time will they completely clear each other vfrom the moment they meet ?
Ans 3.
A train during its course of journey from station A to station B,travels for 2 hours at 30 km.hour, for 3 hours at 40 km/hour and for 5 hour at 50 km/hour, Find its average speed.
Ans 2.
A cyclist covers a certain journey at 50 km/hour and returns at a speed of 60 km/hour. Find his average speed.
Ans 1.
A railway passenger counts the telegraph posts in the railway track as he passes them. if they are 40 metres apart and the train is going at a speed of 24 km/hour how many will he pass per minute?
(a) 15
(b) 10
(c) 13
(d) 16
Ans 10. 10
Note : Try it. Practice question
If 75% of a number is added to 75, then the result is the number itself. The number is :
A) 100
B) 200
C) 300
D) 400
Answer: C) 300
Explanation:
Let the number be x, Then
75% of x + 75 = x
A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are :
A) 500B) 600C) 800D) 1000
Answer: A) 500
Explanation:
Given that the student got 125 marks and still he failed by 40 marks
=> The minimum pass mark = 125 + 40 = 165
Given that minimum pass mark = 33% of the total mark
=>
=>
If 75% of a number is added to 75, then the result is the number itself. The number is :
A) 100
B) 200
C) 300
D) 400
Answer: C) 300
Explanation:
Let the number be x, Then
75% of x + 75 = x
The ratio 5 : 4 expressed as a percent equals :
A) 12.5 %
B) 40 %
C) 80 %
D) 125 %
Answer: D) 125 %
Explanation:
5 : 4 = 5/4 = ( (5/4) x 100 )% = 125%.
405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children. How many sweets did each child recieve ?
A) 9B) 10C) 11D) 12
Answer: A) 9
Explanation:
Let the total number of children be x.
Then, x * (20% of x) = 405
Number of sweets received by each child = 20% of 45 = 9.
A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation ?
A) 54 %
B) 64 %
C) 74 %
D) 84 %
Answer: B) 64 %
Explanation:
Let the number be x.
Then, ideally he should have multiplied by x by 5/3. Hence Correct result was 
By mistake he multiplied x by 3/5 . Hence the result with error =
Then, error =
Error % = 
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