#4 Blood Relationship Question

There is a family of six persons A, B, C, D, E and F. They are Lawyer, Doctor, Teacher, Salesman, Engineer and Accountant There are two married couples in the family. D, the Salesman is married to the Lady Teacher. The Doctor is married to the Lawyer. F, the Accountant is the son of B and brother of E. C, the Lawyer is the daughter-in-law of A. E is the unmarried Engineer. A is the grandmother of F.  What is the profession of A? 

A) Lawyer
B) Teacher
C) Doctor
D) None of these

Answer: B) Teacher 

Explanation:

C is the daughter-in-law of A who is the grandmother of F means C is the mother of F But F is the son of B. 

So. B is C's husband. But C, the lawyer. is married to the Doctor So. B is the Doctor. F. the Accountant, will he the non of B and C E is the unmarried Engineer 

So. the other married couple can be that of grandmother of F. i.e, A and D. But D, the Salesman, is married to the Lady Teacher. 

So. D, the Salesman, is the grandfather of F. father of B and the husband of A. the Lady Teacher. 

A is the Lady Teacher 

#3 Blood Relationship Question

Pointing to a girl in the photograph, Amar said, "Her mother's brother is the only son of my mother's father." How is the girl's mother related to Amar ? 

A) Mother
B) Sister
C) Aunt
D) Grandmother

Answer: C) Aunt 

Explanation:

Only son of Amar's mother's father — Amar's maternal uncle. 

So, the girl's maternal uncle is Arnar's maternal uncle. Thus, the girl's mother is Amar's aunt. 

#2 Blood Relationship Question

All the six members of a family A, B, C, D, E and F are travelling together. B is the son of C but C is not the mother of B. A and C are a married couple. E is the brother of C. D is the daughter of A. F is the brother of B.  Who is the mother of B ? 

A) D
B) F
C) B
D) A

Answer: D) A 

Explanation:

B is the son of C but C is not the mother of B means C is the father of B. A is marned to C means A is the mother of B. F is brother of B means F is son of A and C. D is daughter of A means D is daughter of A and C

Clearly. A is the mother of B. 

#1 Blood Relationship Questions

If Neena says, "Anita's father Raman is the only son of my father-in-law Mahipal", then how is Bindu, who is the sister of Anita, related to Mahipal ? 

A) Daughter
B) Wife
C) Daughter-in-law
D) None of these

Answer: D) None of these 

Explanation:

Only son of Neena's father-in-law Mahipal Neena's husband. So, Raman is Neena's husband and Anita and Hindu are his daughters. 

 Thus, Bindu is the grand daughter of Mahipal. 

#8 Blood Relationship Question

A is B's sister. C is B's mother. D is C's father. E is D's mother. Then, how is A related to D?

A) Grandfather
B) Grandmother
C) Daughter
D) Granddaughter

Answer: D) Granddaughter 

Explanation:

A is the sister of B and B is the daughter of C.

So, A is the daughter of C. Also, D is the father of C.

So, A is the granddaughter of D. 

#103 Average Quantitative Aptitude Question

The average age of a family of 8 members is 23 years. If the age of the youngest membe be 7 years, then what was the average age of the family member at the birth of the youngest member ? 

Solution: Total age of all members= 8 * 23 =184 years

7, years ago, total sum of ages= 184 - ( 8 * 7 ) = 128 years 

But 7 years before there were only 7 members in the family so,

#100 Average Quantitative Aptitude Question

If the average of 50 numbers is 38. If two numbers 45 and 55 are discarded, the average of the remaining number will be ?

#99 Average Quantitative Aptitude Question

The average of five consecutive numbers is n . If the next two numbers are also included, the average will .

(a) increase by 1      (b) remain the same
(c) increase by 1.4      (d) increase by 2

Solution :

#33 Percentage Question

If the pice of sugar rises from Rs. 6 per kg to Rs. 7.50 per kg, a person, to have no increase in his expenditure on sugar, will have to reduce his consumpion of sugar by

A) 15

B) 20

C) 25

D) 30

Answer: B) 20 

Explanation:

 Let original consumption = 100 kg and new consumption = x kg,

So,  

Reduction in consumption = 20%.

#32 Percentage Question

A district has 64000 inhabitants. If the population increases at the rate of 2 * 1/2 % per annum, then the number of inhabitants at the end of 3 years will be : 

A) 65380
B) 68921
C) 70987
D) 72345

Answer: B) 68921 

Explanation:

Population afer 3 years = 64000 * (1 +  5/(2 *100) )^3 = (64000 * 41/40 * 41/40 * 41/40 ) = 68921..

#31 Percentage Question

A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :

A) 21.6 %
B) 15.3 %
C) 14.6 %
D) 12.5 %

Answer: A) 21.6 % 

Explanation:

Total money =  = Rs. 750.

25 paise coins removed == 72.

50 paise coins removed = = 288.

Money removed =  = Rs.162.

Required percentage = % = 21.6 %.

#29 Percentage Question

In a City, 35% of the population is composed of migrants, 20% of whom are from rural areas. Of the local population, 48% is emale while this figure for rural and urban migrants is 30% and 40% respectively. If the total population of the city is 728400, what is its female population ?

A) 856678
B) 860990
C) 896660
D) 908790

 Answer: C) 896660 

Explanation:

Migrants = 35 % of 728400  = (35x/100 * 728400) = 254940.
local population = (728400 - 254940) = 473460.

Rural population = 20% of 473460 = 94692.

Urban population = (254940 - 94692) = 160248.

Female population = 48% of 473460 + 30% of 94692 + 40% of 160248

 = (48/100 * 473460 + 30/100 * 94692 + 40/100 * 160248)

   = 227260.8 + 28407.6 + 64099.2 = 896660

#28 Percentage Question

The sum of the number of boys and girls in a school is 150. if the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is : 

A) 60
B) 70
C) 80
D) 90

Answer: A) 60 

Explanation:

We have : x + x% of 150 = 150

=> 

=> 

=> 

#27 Percentage Question

A candidate scoring 25% in an examination fails by 30 marks , while another candidate scores 50 % mark, gets 20 marks more than the minimum pass marks . Find the minimum pass marks. Find the minimum pass percentage.

 Answer

Let x be the maximum marks, 

Then (25% of x)+30 = (50% of x)-20

 

Hence maximum marks = 200

Minimum pass marks = 

Hence, minimum pass marks = %

#26 Percentage Question

In some quantity of ghee, 60% is pure ghee and 40% is vanaspati. If 10 kg of pure ghee is added, then the strength of vanaspati ghee becomes 20%. The original quantity was : 

A) 10 kg
B) 15 kg
C) 20 kg
D) 25 kg

Answer: A) 10 kg 

Explanation:

Let the original quantity be x kg. Vanaspati ghee in x kg  =  (40x / 100 )kg = (2x / 5) kg.

Now, (2x/5)/(x + 10) = 20/100 <=> 2x / (5x + 50) = 1/5  <=> 5x = 50  <=> x = 10.

#30 Percentage Question

Entry fee in an exhibition was Rs. 1. Later, this was reduced by 25% which increased the sale by 20%. The percentage increase in the number of visitors is :

A) 20 %
B) 40 %
C) 60 %
D) 80 %

Answer: C) 60 % 

Explanation:

Let the total original sale be Rs. 100. Then, original number of visitors = 100.

New number of visitors  =  120/0.75 = 160.

Increase % = 60 %.

#25 Percentage Question

In an election only two candidates contested 20% of the voters did not vote and 120 votes were declared as invalid. The winner got 200 votes more than his opponent  thus he secured 41% votes of the total voters on the voter list. Percentage votes of the defeated candidate out of the total votes casted is:

A) 47.5%
B) 41%
C) 38%
D) 45%

Answer: D) 45% 

Explanation:

Let there be x voters and k votes goes to loser then 

      0.8x - 120 = k + (k + 200)

         k+200 = 0.41x

          k = 1440

and  (k + 200) =1640

Therefore   = 45%

#24 Percentage Question

If x is 80% of y, then what percent of 2x is y?

A) 65.5 %
B) 64.5 %
C) 63.5 %
D) 62.5 %

Answer: D) 62.5 % 

Explanation:

 x = 80 % of y    

Required percentage =  % = % =62.5%

#23 Percentage Question

1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is :

A) 58
B) 62 *2/3
C) 64
D) 67

Answer: B) 62 *2/3 

Explanation:

Total number of students = 1100 + 700 = 1800.

Number of students passed = (42% of 1100 + 30% of 700) - (462 + 210) = 672.

Number of failues = 1800-672 = 1128.

Percentage failure = (1128/1800 * 100 )% = 62 * 2/3 %. 

#22 Percentage Question

Of the 1000 inhabitants of a town, 60 % are males of whom 120 % are literate. If, of all the inhabitants,  25% are literate, then what percent of the females of the town are literate ?

A) 32.5 %
B) 43 %
C) 46.6 %
D) 53.2 %

Answer: A) 32.5 % 

Explanation:

Number of males = 60% of 1000 = 600. Number of females = (1000 - 600) = 400.

Number of literates = 25% of 1000 = 250.

Number of literate males = 20% of 600 = 120.

Number of literate females = (250 - 120) = 130.

Required pecentage = (130/400 * 100 ) % = 32.5 %.