A cicketer bas a certain average for 10 innings, In the eleventh inning, he scorod 108 runs, thereby increasing his average by 6 runs. His new average is :
A) 44 runs
B) 46 runs
C) 48 runs
D) 49 runs
Answer: C) 48 runs
Explanation:
Let average for 10 innings be x. Then,
(10x + 108)/11 = x + 6 => 11x + 66 = 10x + 108 => x = 42.
New average = (x + 6) = 48 runs.
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